Question

Calculus: Find the derivative.
y=x/(square root of 2x-3)

Answer 1

\[x \div \sqrt{2x-3}\]

Answer 2

Do you know the divide rule for derivative ??

Answer 3

low d high - high d low? :o

Answer 4

It is :
\[\frac{x}{\sqrt{2x - 3}}\]

Answer 5

I would use product rule...

Answer 6

Yes you can use whatever you want...

Answer 7

can you show me how u get the answer because i did both rules and i didn't get the same answer from what my teacher gave me :\

Answer 8

X*(2x-3)^(-1/2)

Answer 9

Divide rule says :

\[\frac{u}{v} = \frac{v \cdot u' - u \cdot v'}{v^2}\]

Answer 10

Can you show your steps if you have solved from both the rules ??

Answer 11

Uv'+vu'

U=x
U'=1
V= (2x-3)^(-1/2)
V'= -(2x-3)^(-3/2)

Answer 12

I erased it already xD

Answer 13

Substitute, simplify .

Answer 14

You can do it here..

I just want to see that how you have done it so that we can find the mistake..

Answer 15

ok but product rule is better since there is only x at the top rite?

Answer 16

Mine was product rule. Either works. Take your pick.

Answer 17

Well you have negative exponents but it works fine.

Answer 18

What is the difficulty you are facing in using divide rule ??