Question

some one pllzzz help me


factor and each of the following quadratic equations

16b^2-25=0

Answer 1

transpose - 25 to Right Hand Side
16b^2 = 25
then divide both sides by 16
b^2 = 25/16

can u solve now???

Answer 2

@this
Did you understand what I replied

Answer 3

no really but i will try

Answer 4

have u understood the two steps that i have given??

Answer 5

transpose - 25 to Right Hand Side
16b^2 = 25
then divide both sides by 16
b^2 = 25/16
now take square root of both sides, we get
b = +/- sqrt(25)/sqrt(16) = +/- 5/4 or (+/- 1.25 in decimal form)

Answer 6

16b^2 can be written as (...)^2 ?
what comes inside brackets?

Answer 7

16b^2-25=0
add 25 on both side(or the left hand side and the right hand side)
16b^2-25+25=0+25
16b^2=25 divide 16 0n both sides we get
16/16b^2=25/16
b^2=25/16 now square root both sides to get
(b^2)^1/2=(25/16)^1/2 or
\[\sqrt{b ^{2}}=\sqrt{\frac{ 25 }{ 16 }}\]
\[b=\frac{ \sqrt{25} }{ \sqrt{16} }\]
\[b=\frac{ 5 }{ 4 }\]

Answer 8

why is ever1 solving it without factoring, when the question clearly says to factor it :\

Answer 9

now that we know b=5/4
(b-5/4)(b+5/4)=0 multiply both sides by 4
(4b-5)(4b+5)=0

Answer 10

from b =+-sqrt(25/16)
b=+- 5/4

now that we know b=-5/4 and +5/4
(b-5/4)(b+5/4)=0 multiply both sides by 4
(4b-5)(4b+5)=0