ok need help
\[\frac{ x }{ x-4 }=\frac{ x+4 }{ 6 }\]
i know the awnser just dont know how to get there
multiply the denominator of one side by the numerator of the other. then repeat with the other denominator. you should get 6x = (x-4)(x+4). FOIL the right side and set everything equal to zero by subtracting 6x from both sides. then use the quadratic formula
Do cross-multiply. Do you know what it is?
ya but when it comes t foil its where im getting stuck i know the awnser is -2 and 8 but like 6x=\[\left( x \right)\left( x \right)\] what multipllys to be 16 but adds to be -4
x^2+6x-16 = 0 (x+8)(x-2) x=2,-8
wait, error in the last one...forgot 6x should be negative
x^2-6x-16 = 0 (x-8)(x+2) x=-2,8
oh s i should have replaced the middle number with 6x
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