Question

ok one more for the night

Answer 1

are you answering questions or asking one?

Answer 2

\[\left( \frac{x ^{2}-10x+16 }{ 4x-8} \right)\div \left( \frac{ x ^{2}-11x+24 }{2x ^{2}-18 } \right)\]

Answer 3

asking i know you flip the second one

Answer 4

oh sorry im asking too...but yes from what i know you flip the second one but im not sure how to multiple it out

Answer 5

can u factor x^2-10x+16 ?

Answer 6

i get \[(x-8)(x-2)\]

Answer 7

that is correct, now factor x^2-11x+24

Answer 8

(x-8)(x-3)

Answer 9

correct again!
what about 2x^2-18 ?

Answer 10

thats wjere i get stuck i get

Answer 11

2x^2-18 = 2(x^2-9)
now ?
observe that it is difference of squares.

Answer 12

so it breaks down to \[\left( 2(x ^{2}-9 \right)\]

Answer 13

\(x^2-9 = x^2-3^2 = ? \)
use
\(\large a^2-b^2=(a+b)(a-b)\)

Answer 14

(2x+3)(x-3)

Answer 15

2 will remain outside
2(x+3)(x-3)
ok?

Answer 16

now put everything together, in the fraction form,
after flipping the 2nd one

Answer 17

so what about the 4x-8

Answer 18

factor out 4 from that

Answer 19

4(x-8)

Answer 20

4x-8 = 4x-4*2 = 4(x-2)
got this ?

Answer 21

\[\frac{ (x-8)(x-2) }{ 4(x-2) }\times \frac{ (2(x+3)(x-3) }{ (x-8)(x-3) }\]

Answer 22

\[\frac{ 2x+3 }{ 4 }\]

Answer 23

absolutely correct!
what gets cancelled out ?

Answer 24

ok, again u missplaced the brackets
won't it be 2(x+3 ?)

Answer 25

2(x+3)/4

Answer 26

oh yes \[\frac{ 2(x+3) }{ 4 }\]

Answer 27

which gets simplified to ?

Answer 28

\[\frac{ (x+3 }{ 1 }\]

Answer 29

2/4=?

Answer 30

\[\frac{ x+3 }{ 2 }\]

Answer 31

that is correct final answer :)

Answer 32

o thank youuuuuuu soo much

Answer 33

welcomeeeeeee soo much ^_^