Mathematics
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OpenStudy (anonymous):
Solve the following equations for all solutions of x
2sin^2x+3cos-3=0
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hartnn (hartnn):
u need to convert sin^2 x into cos^2 x
which i dentity u know of, does this ?
hartnn (hartnn):
an identity relating sin^2 x and cos^2 x is ?
OpenStudy (anonymous):
Pythagorean?
hartnn (hartnn):
yes, state that or find sin^2 x from that, what u get ?
OpenStudy (anonymous):
sin^2x+cos^2x=1
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hartnn (hartnn):
yes so sin^2 x from ^ will be ?
OpenStudy (anonymous):
1+cos^2x
hartnn (hartnn):
sin^2x+cos^2x=1
so
sin^2 x = 1-cos^2 x
got this ??
OpenStudy (anonymous):
Oh...yeah, yeah, yeah
hartnn (hartnn):
now put that in 2sin^2x+3cos-3=0
and u get an equation only in terms of cos x
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OpenStudy (anonymous):
2cos^2x+3cos-1=0?
hartnn (hartnn):
2sin^2x+3cos-3=0
2-2cos^2x +3cos x -3 = 0
-2cos^2 x + 3cos x -1 = 0
2cos^2 x -3cos x +1 = 0
got this ?
OpenStudy (anonymous):
Yes...now I have 2cos^x-3cosx+1=0
hartnn (hartnn):
now put cos x =y
so u get a quadratic in y
can u solve quadratic equations ?
OpenStudy (anonymous):
Just with a=2,b=-3,c=1?
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hartnn (hartnn):
yes :) so u know the formula ?
OpenStudy (anonymous):
Yeah
OpenStudy (anonymous):
So is there going to be two answers then?
hartnn (hartnn):
what 2 answers u got ?
OpenStudy (anonymous):
I came up with x=3+-sqrt72/4
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OpenStudy (anonymous):
Unsure though...
hartnn (hartnn):
72? b^2-4ac = (-3)^2 - 4(2)(1) = 9-8 = ?
OpenStudy (anonymous):
Ugh....I multiplied x4ac
So...9-8=1
hartnn (hartnn):
yes, so two values of y are >?
OpenStudy (anonymous):
Is it 3+-1/4?
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hartnn (hartnn):
so 2 values are ?
OpenStudy (anonymous):
13/4,11/4?
hartnn (hartnn):
13 ? 11 ?
(3+1)/4 or (3-1) /4
so, 4/4 or 2/4
so, 1 or 1/2
ok?
OpenStudy (anonymous):
OMG...sorry. I was taking 3+1/4
It's all over 4, yes
hartnn (hartnn):
so u have cos x =1 or cos x = 1/2
right ? can u solve this 2 equations ?
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OpenStudy (anonymous):
So cosign of 1 is pi/2
OpenStudy (anonymous):
And pi/6?
hartnn (hartnn):
cos (0) = 1
cos (pi)= 1
so cos x =1 will give x= 0,pi,2pi,....n*pi
OpenStudy (anonymous):
Thank you so much for your time. These processes are very hard for me. I know practice will help. Thank you again for walking me through each step.
hartnn (hartnn):
still cos x =1/2 is remaining
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OpenStudy (anonymous):
So if cosx=1/2 then @ pi/3?
hartnn (hartnn):
yes, and other values ?
OpenStudy (anonymous):
Also 5pi/3 @ 300deg
OpenStudy (anonymous):
Thank goodness for a unit circle :)
hartnn (hartnn):
yeah, in general, it will be pi/3 + 2n*pi
x= pi/3 , pi/3+ 2pi, pi/3 + 4pi, ...pi/3 + 2n*pi