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2^3/2^-2
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\[\frac{ 2^3 }{ 2^{-2} }\]
Wouldn't it be 8/.25
Do you know these exponent properties? \[ \huge a^{-b} = \frac{1}{a^b} \\ \huge \frac{a^n}{a^m} = a^{n-m}\]
So you can do this: \[\Large \frac{2^3}{2^{-2}} = \frac{2^3}{\frac{1}{2^2}} = 2^3 2^2 = 2^{3 + 2} = 2^5\]\[\Huge\text{OR}\]\[\Large \frac{2^3}{2^{-2}} = 2^{3 - (-2)} = 2^{3 + 2} = 2^5\]
@micahwood50 Nice.
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Is this clear? @ctccbuggs
I have a feeling that you're Myin.
Yes, thanks @micahwood50.
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