Question

Sides of a quadrilateral are all positive integers . Three of them are 5,10,20 . How many possible values are there for the fourth side?

Answer 1

length of 4th side = X
therefore, 5 < X < 35

Answer 2

The shortest 4th side will have length of 6, and the longest 4th side will have length of 34. All values from 6 to 34 are possible. understood?

Answer 3

i didn,t understood

Answer 4

In a quadrilateral, the sum of any three sides of a quadrilateral is greater than the length of the fourth side. by using this identity we can get the above said answer

Answer 5

yes i understood this answer thanks
can you tell me another answer

Answer 6

what answer?

Answer 7

welcome :)

Answer 8

answer is 29

Answer 9

31 values also possible if u take extreme digits(5 and 35).. but it ll look like a straight line :).. co considering it as a non zero area quadrilateral, we ll assume the values from 6 to 34.. so we get answer as 29 values :)... now u can get it clearly..

Answer 10

find the greatest 5 digit no. which is exactly divisible by 7,10,15,21,28 please tell me the short trick to do this

Answer 11

ok... first take the lcm of 7,10,15,21,28

Answer 12

u know abt taking lcm, right?

Answer 13

lcm is 420

Answer 14

ok... now lets consider greatest 5 digit number as 99999... divide this number with 420 and tel me the reminder

Answer 15

u got it?

Answer 16

the answer is 99960... (procedure is u should first find the lcm and divide the number with the lcm... then subtract the number with the reminder... thats the answer..)

Answer 17

yes it's 459

Answer 18

dividing 99999/420 will give u a reminder of 39.. so the greatest 5 digit no divided by 7,10,15,21,28 is

99999-39=99960.

Answer 19

wat class r u studying?

Answer 20

10

Answer 21

mmm... try to be fast at divisions.. correct errors.. remember that the reminder ll be always less than divisor.. 99999/420 wont give 459 as reminder because 459 still dividible by 420.. so reminder is 39.. ok?

Answer 22

thanks you are a great guy

Answer 23

hahaha.. welcome.. no one in this world is great.. its all about how we use our intellegence :)

Answer 24

if both 11^2 and 3^3 are the factors of the number a x 4^3 x 6^2 x 13^11. then what is the smallest possible value of a

Answer 25

pls tell me

Answer 26

first prime factorise a*4^3*6^2*13^11

Answer 27

there is a large no. 13^11 pls tell

Answer 28

pls tell

Answer 29

a x 4^3 x 6^2 x 13^11
=a x 2^6 x (2^2 x 3^2) x 13^11
=a x 2^8 x 3^2 x 13^11... this s called prime factorizing... u writing any online exam now?

Answer 30

i have done pls tell after this

Answer 31

ans is 363

Answer 32

how

Answer 33

Since 3^3 is a factor (with 3^2 already accounted apart from a), therefore 'a' must contain at least one multiple of 3.

Since 11^2 is a factor and has not been accounted anywhere else,therefore 'a' must contain 11^2.

Therefore, a must be at least 11^2 x 3 = 363.

Answer 34

thanks
Actually i have applied for akash talent hunt exam so that's why i am solving a sample paper of this and asking questions from you

Answer 35

you have any idea of this exam or not?
if yes then pls tell what i prepare for this exam

Answer 36

i know abt dis exam n the syllabus ... but i didn know about question types n al.. better prepare with model q.papers.. al the best :)

Answer 37

there is only one sample paper i have found on net can you tell me another site for these type sample paper
and should i prepare from my ncert book or another like tougher one pls tell

Answer 38

i duno abt it... but ncert books are enough with concepts clearly understood.. for gk get any small gk book available in stores for rs 20 or 30

Answer 39

tell me aptitude questions because that are also coming in exam

Answer 40

pls tell

Answer 41

tell na pls

Answer 42

for aptitude use 'quantitative aptitude' by R S agarwaal or 'magical book on quicker maths' by M.Tyra