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Mathematics 15 Online
OpenStudy (anonymous):

Factor: x^4-2x^3+x^2+8x-5 Try it manually...how is it done?

Parth (parthkohli):

Use the rational roots test?

OpenStudy (anonymous):

try it

Parth (parthkohli):

Okay. The possible rational roots are: 5 -5 1 -1

Parth (parthkohli):

Checking all of them. Gimme a sec.

hartnn (hartnn):

forget 1,-1

Parth (parthkohli):

Yup, not 1 and -1.

Parth (parthkohli):

not 5.

hartnn (hartnn):

no rational roots

OpenStudy (anonymous):

yeah, but it can still be factorised

OpenStudy (anonymous):

into two quadratics... what's the point here?

OpenStudy (anonymous):

Well...you're factoring it I guess you could get the roots But how do you get to the quadratics?

Parth (parthkohli):

Yeah, we can.

hartnn (hartnn):

i may suggest a way, (x^2+ax+b)(x^2+cx+d) = x^4-2x^3+x^2+8x-5 and compare the co-efficients, 4 unknowns

hartnn (hartnn):

like bd=-5

Parth (parthkohli):

Like for example, we have \(\sqrt2{}\) as a root, then a factor would be \(\rm x^2 - 2\).

OpenStudy (anonymous):

Well, @hartnn 's way is very good to get the quadratics

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