if the permeter of a rectangle is 60 meters and its area is 200 square meter then one of it's sides must be ------ the other?
options:
A=one third of
B=triple
C=double
D=one tenth of
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
Parth (parthkohli):
Do you know how to solve simultaneous equations?
OpenStudy (anonymous):
yes
Parth (parthkohli):
So the equation says that if 'a' and 'b' are the two adjacent sides, then:
ab = 200
2(a + b) = 60
OpenStudy (anonymous):
draw out a rectangle
you should have 2 lengths and 2 widths
just remember perimeter = l + l + w + w
and area = length times width
Parth (parthkohli):
@laraib Can you solve the equation I gave ya?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes m solving
Parth (parthkohli):
If I were you, I'd be using the eyeball method.
OpenStudy (anonymous):
how? tell me plz
Parth (parthkohli):
Two numbers that add up to 30 and multiply to get 200.
Parth (parthkohli):
Clearly, those numbers are 20 and 10 right?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes that's how i solved it
Parth (parthkohli):
very good! So now look at the choices you have in your question.
OpenStudy (anonymous):
it would be DOUBLE.right?
Parth (parthkohli):
Yes :)
OpenStudy (anonymous):
thanks.
can u plz suggest me any website from where i can prepare for aptitude test of universities?
Still Need Help?
Join the QuestionCove community and study together with friends!