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OpenStudy (anonymous):
What is the percent composition of calcium acetate (Ca(C2H3O2)2) Please show work!
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OpenStudy (mayankdevnani):
gd question @malutella
OpenStudy (anonymous):
do you know how to work this problem?
OpenStudy (mayankdevnani):
yaa
OpenStudy (mayankdevnani):
First, you have to find the molar mass of the compound :- ca : 1 X 40.1 = 40.1 c: 4 x 12.01 = 48.04 H: 6 X 1.01 = 6.06 O: 4 X 16 = 64 add these up and get 158.11 then divide 158.11 by each element mass and multiply by 100 Ca: 40.01/158.11 X 100 = 25.3% C: 30.4% H:3.8% O: 40.5%
OpenStudy (mayankdevnani):
got it @malutella
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OpenStudy (anonymous):
Thank youuu!!!
OpenStudy (mayankdevnani):
welcome..
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