Question

The percent composition of methyl butanoate is 58.8% C, 9.8% H, and 31.4 % O and its molar mass is 102 g/mol. What is its empirical formula? What is its molecular formula? @mayankdevnani

Answer 1

Assume you have 100g and you can convert % to g.
m(C) = 58.8g
m(H) = 9.8g
m(O) = 31.4g

n(C) = m/M = 58.8g / 12g/mol = 4.9mol
n(H) = m/M = 9.8g / 1g/mol = 9.8mol
n(O) = m/M = 31.4g / 16g/mol = 2.0mol

These ratios are C:H:O 5:10:2 (after rounding off)
So the empirical formula is C5H10O2

This compound has a molecular mass of:
m=nM = 12x5 + 1x10 + 16x2 = 60+10+32 = 102g/mol

Answer 2

got it @malutella

Answer 3

ok @malutella

Answer 4

Thank youu!

Answer 5

welcome