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OpenStudy (mayankdevnani):

A steam engine has an efficiency of 20%.It is given an energy of 1000 cal.per minute.What is the actual work done by it in joule and in calories? a) 100 cal,800 J b) 200 cal,873 J c)10 cal,80 J d)100 cal,100 J

OpenStudy (mayankdevnani):

@amistre64 @ParthKohli @hartnn @Callsito @Zarkon @Hero @.Sam. @estudier @ganeshie8 @ajprincess @Algebraic!

OpenStudy (mayankdevnani):

@Callisto

OpenStudy (amistre64):

im not sure since we havent gone over this in my physics class yet, but i would say that 20% efficiency means that 20% of the 1000 cals are used; giving us 200 cals in the answer at least

OpenStudy (anonymous):

May I help?

OpenStudy (amistre64):

please do :)

OpenStudy (mayankdevnani):

ofcourse @SheldonEinstein

OpenStudy (anonymous):

;) OK so first of all what @amistre64 discussed in his previous comment is very imp. to do this quest., so @mayankdevnani do you know what does efficiency mean?

OpenStudy (mayankdevnani):

ok @amistre64 then

OpenStudy (mayankdevnani):

yaa

OpenStudy (mayankdevnani):

efficiency=winout/winin*100

OpenStudy (mayankdevnani):

right @SheldonEinstein

OpenStudy (anonymous):

Yeah or in simpler words it is : \(\large{\frac{\textbf{Output}}{\textbf{Input}}\times 100}\) it is 100%...

OpenStudy (mayankdevnani):

yaa

OpenStudy (anonymous):

So, what we have is output/input * 100% = 20% , correct?

OpenStudy (mayankdevnani):

correct

OpenStudy (anonymous):

Ok so now, let me understand the second line of the quest. , is the output = 1000 calorie ?

OpenStudy (mayankdevnani):

yaa

OpenStudy (mayankdevnani):

then

OpenStudy (mayankdevnani):

@SheldonEinstein then

OpenStudy (anonymous):

Oh sorry wait!

OpenStudy (mayankdevnani):

yaa

OpenStudy (anonymous):

I am getting diff. answer so I am checking it, sorry , it will require some patience.

OpenStudy (mayankdevnani):

ok

OpenStudy (anonymous):

Quest. is wrong

OpenStudy (mayankdevnani):

why?? no it is right

OpenStudy (anonymous):

Time is not given.. though if you take 1 minute it is 200 cal.

OpenStudy (mayankdevnani):

yaa

OpenStudy (anonymous):

See , Power = 1000 cal/minute (given)

OpenStudy (anonymous):

use this and you will get 200 cal. as answer.

OpenStudy (mayankdevnani):

so what's the work done?

OpenStudy (anonymous):

W = P * time if T = 1 second , W = P ... that's it , find P(output) .. (using efficiency = Ouput/Input *100%) in Cal. per minute , that will be your answer

OpenStudy (anonymous):

200 cal.... = WORK DONE

OpenStudy (mayankdevnani):

no

OpenStudy (mayankdevnani):

but the work done is in joule

OpenStudy (mayankdevnani):

@ParthKohli @Preetha

OpenStudy (mayankdevnani):

@SheldonEinstein

OpenStudy (mayankdevnani):

@myininaya

OpenStudy (anonymous):

Is my answer correct, i.e. 200 cal, 873 J ?

OpenStudy (mayankdevnani):

yaa

OpenStudy (anonymous):

So where is the problem? ?? ? ?

OpenStudy (mayankdevnani):

873 J how??

OpenStudy (mayankdevnani):

@amriju

OpenStudy (mayankdevnani):

@SheldonEinstein how you got it 873J

OpenStudy (anonymous):

I got 200 Cal, and it is in options, soo....

OpenStudy (mayankdevnani):

but it's wrong

OpenStudy (mayankdevnani):

i need solution

OpenStudy (mayankdevnani):

can you help me @amriju

OpenStudy (anonymous):

200 cal * 4.184 = 836 J (approx. ) not equal to 873 Joule , hence I think the options are wrong..

OpenStudy (mayankdevnani):

no it was not wrong

OpenStudy (amriju):

work done is 20 percnt of the energy given...thats efficiency....so per minute is 20percnt of 1000 cal...thats 200 cal...convert to joules

OpenStudy (mayankdevnani):

so 1cal.=? j @amriju

OpenStudy (amriju):

4.2...approx..the correct is 4.187...

OpenStudy (mayankdevnani):

is it 4.37

OpenStudy (amriju):

nope

OpenStudy (mayankdevnani):

why??

OpenStudy (amriju):

thats how it is defined...both are units...and 1 cal is defined as 4.187 joules...

OpenStudy (anonymous):

That is what I was saying @amriju

OpenStudy (mayankdevnani):

in my solution book...the answer is as follows- \[\frac{20}{100}=\frac{W}{1000}=200 calorie\] OR \[200\times4.37=873J\]

OpenStudy (mayankdevnani):

is that right?? @amriju and @SheldonEinstein

OpenStudy (anonymous):

That is wrong, 1 Cal. = 4.187 Joule NOT 4.37 joule...

OpenStudy (mayankdevnani):

ok... thnx... @SheldonEinstein and @amriju

OpenStudy (amriju):

u may jst check on wikipedia...and its seems that none of the options are correct...the closest being 200, 837

OpenStudy (amistre64):

just for reference http://www.wolframalpha.com/input/?i=200+calorie+to+joule

OpenStudy (amistre64):

if your options are truely: 200,873 then its most likely a typo and prolly meant to be read as 200,837

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