A steam engine has an efficiency of 20%.It is given an energy of 1000 cal.per minute.What is the actual work done by it in joule and in calories?
a) 100 cal,800 J
b) 200 cal,873 J
c)10 cal,80 J
d)100 cal,100 J
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im not sure since we havent gone over this in my physics class yet, but i would say that 20% efficiency means that 20% of the 1000 cals are used; giving us 200 cals in the answer at least
OpenStudy (anonymous):
May I help?
OpenStudy (amistre64):
please do :)
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OpenStudy (mayankdevnani):
ofcourse @SheldonEinstein
OpenStudy (anonymous):
;) OK so first of all what @amistre64 discussed in his previous comment is very imp. to do this quest., so @mayankdevnani do you know what does efficiency mean?
OpenStudy (mayankdevnani):
ok @amistre64 then
OpenStudy (mayankdevnani):
yaa
OpenStudy (mayankdevnani):
efficiency=winout/winin*100
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OpenStudy (mayankdevnani):
right @SheldonEinstein
OpenStudy (anonymous):
Yeah or in simpler words it is : \(\large{\frac{\textbf{Output}}{\textbf{Input}}\times 100}\) it is 100%...
OpenStudy (mayankdevnani):
yaa
OpenStudy (anonymous):
So, what we have is output/input * 100% = 20% , correct?
OpenStudy (mayankdevnani):
correct
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OpenStudy (anonymous):
Ok so now, let me understand the second line of the quest. , is the output = 1000 calorie ?
OpenStudy (mayankdevnani):
yaa
OpenStudy (mayankdevnani):
then
OpenStudy (mayankdevnani):
@SheldonEinstein then
OpenStudy (anonymous):
Oh sorry wait!
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OpenStudy (mayankdevnani):
yaa
OpenStudy (anonymous):
I am getting diff. answer so I am checking it, sorry , it will require some patience.
OpenStudy (mayankdevnani):
ok
OpenStudy (anonymous):
Quest. is wrong
OpenStudy (mayankdevnani):
why?? no it is right
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OpenStudy (anonymous):
Time is not given.. though if you take 1 minute it is 200 cal.
OpenStudy (mayankdevnani):
yaa
OpenStudy (anonymous):
See , Power = 1000 cal/minute (given)
OpenStudy (anonymous):
use this and you will get 200 cal. as answer.
OpenStudy (mayankdevnani):
so what's the work done?
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OpenStudy (anonymous):
W = P * time
if T = 1 second , W = P ...
that's it , find P(output) .. (using efficiency = Ouput/Input *100%) in Cal. per minute , that will be your answer
OpenStudy (anonymous):
200 cal.... = WORK DONE
OpenStudy (mayankdevnani):
no
OpenStudy (mayankdevnani):
but the work done is in joule
OpenStudy (mayankdevnani):
@ParthKohli @Preetha
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OpenStudy (mayankdevnani):
@SheldonEinstein
OpenStudy (mayankdevnani):
@myininaya
OpenStudy (anonymous):
Is my answer correct, i.e. 200 cal, 873 J ?
OpenStudy (mayankdevnani):
yaa
OpenStudy (anonymous):
So where is the problem? ?? ? ?
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OpenStudy (mayankdevnani):
873 J how??
OpenStudy (mayankdevnani):
@amriju
OpenStudy (mayankdevnani):
@SheldonEinstein how you got it 873J
OpenStudy (anonymous):
I got 200 Cal, and it is in options, soo....
OpenStudy (mayankdevnani):
but it's wrong
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OpenStudy (mayankdevnani):
i need solution
OpenStudy (mayankdevnani):
can you help me @amriju
OpenStudy (anonymous):
200 cal * 4.184 = 836 J (approx. ) not equal to 873 Joule , hence I think the options are wrong..
OpenStudy (mayankdevnani):
no it was not wrong
OpenStudy (amriju):
work done is 20 percnt of the energy given...thats efficiency....so per minute is 20percnt of 1000 cal...thats 200 cal...convert to joules
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OpenStudy (mayankdevnani):
so 1cal.=? j @amriju
OpenStudy (amriju):
4.2...approx..the correct is 4.187...
OpenStudy (mayankdevnani):
is it 4.37
OpenStudy (amriju):
nope
OpenStudy (mayankdevnani):
why??
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OpenStudy (amriju):
thats how it is defined...both are units...and 1 cal is defined as 4.187 joules...
OpenStudy (anonymous):
That is what I was saying @amriju
OpenStudy (mayankdevnani):
in my solution book...the answer is as follows-
\[\frac{20}{100}=\frac{W}{1000}=200 calorie\]
OR
\[200\times4.37=873J\]
OpenStudy (mayankdevnani):
is that right?? @amriju and @SheldonEinstein
OpenStudy (anonymous):
That is wrong, 1 Cal. = 4.187 Joule NOT 4.37 joule...
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OpenStudy (mayankdevnani):
ok... thnx... @SheldonEinstein and @amriju
OpenStudy (amriju):
u may jst check on wikipedia...and its seems that none of the options are correct...the closest being 200, 837