Question

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

Answer 1

@amistre64 @SheldonEinstein

Answer 2

I know this, wait!

Answer 3

@AshleyBcdd prefer to draw a diagram of it first, I mean that of condition

Answer 4

initial linear momentum=final linear momentum
so
0.08*0.5=-0.1*0.08+0.05*v
v=0.96

Answer 5

Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision...

Now here is the condition of the marbles AFTER collision in the form of a diagram...

Answer 6

now using the law of conservation of momentum :

Momentum before collision = Momentum after collision

@AshleyBcdd are you getting what I am telling here?

Answer 7

\[\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }\]
\[\large{0.08 kg\times (0.05 ms^{-1}) + 0.05 kg \times 0 ms^{-1} = 0.08 kg \times -0.01 ms^{-1} \\+ 0.05 kg \times v_B }\]

Answer 8

you will get : 0.096 after solving for v_B

Answer 9

I'm sorry i was away, yes i understand! thankyou so much :)

Answer 10

You're welcome....