Question

f(x)=3x^3+4x^2-x+C and f(2)=1 what is the value of c

Answer 1

put in '2' for 'x' and set the whole thing equal to '1'... then find C

Answer 2

ok im trying it

Answer 3

so I get fx=3(8)+4(4)-x+c

Answer 4

Replace all x with 2
So you should have f(2)=3(8)+4(4)-2+c which can be simplified more so

Answer 5

Then set that =1 and solve for c

Answer 6

you would get : fx=3(8)+4(4)-2+c = 1
now c is easy to find,right?

Answer 7

im trying to work it

Answer 8

c = 1 - 24 - 16 + 2 which is: -37

Answer 9

C=-37