Question

Midterm Q2: VS=5.0V, VOH=4.5V, VIH=4.0V, VIL=1.5V, VOL=1.0V
VT=2.0V and RON=6000.0Ω.

Answer 1

low noise margin=VIL-VOL=0.5
HIGH NOISE MARGIN=VOH-VIH=0.5
forbidden region=VIH-VIL=2.5
RpuI=4*RON=24000
RpuA=8*RON=48000
RpuO=4*RON=24000
power for inverter=0.000833
power for NAND=0.000416
power for NOR=0.000925

Answer 2

Danke!!!

Answer 3

if RON=16000.0Ω.
power for inverter=?
power for NAND=?
power for NOR=?

Answer 4

?

Answer 5

if ron=16000, for inverter==>p=19.992/Rpul
for nand,==>p=19.968/Rpua
for nor,==>p=22.2/rpuo
bcz,P=(v^2)/R
i gave you v^2 from above answer in reverse way

Answer 6

@apurvdixit713

Answer 7

@apurvdixit713
power for inverter=(Vs^2)/(RpuI+RON)
power for NAND=(Vs^2)/(RpuA+2RON)
power for NOR=(Vs^2)/(RpuO+(RON//RON))