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OpenStudy (anonymous):
Calculate the number of grams of H2O that will form on decomposition of 0.10 mole of ammonium nitrate.
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OpenStudy (anonymous):
@naveedimtiaz ..... 3.6
OpenStudy (anonymous):
Answer=3.6 gms [ i.e NH4NO3→N2O+2H2O 1mol of NH4NO3->2mols of H2O 0.1mol of NH4NO3 ->0.2 mols of H2O ie,0 .1 mol of NH4NO3 -> 0.2*18gms . because ( 1mol of H2O=18 gms)]
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