Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Any reason why i cant rewrite this integral as this?

OpenStudy (anonymous):

\[\int\limits \frac{ COS(\sqrt{X} }{ \sqrt{X} } = \int\limits COS (x ^{1/2}) * x ^{-1/2}\]

OpenStudy (amistre64):

thats fine

OpenStudy (anonymous):

Then i can just use by parts to solve it.

OpenStudy (amistre64):

you can always give it a shot

OpenStudy (amistre64):

or we can assume that this MIGHT come from something similar to sin(x^(.5)) \[D_x[sin(x^{.5})]=\frac{cos(x^{.5})}{2x^{.5}}\] notice that if we introduce a constant 2 at the onset, we get what we are looking for \[D_x[2sin(x^{.5})]=\frac{2~cos(x^{.5})}{2~x^{.5}}\]

OpenStudy (amistre64):

and of course any general "+C" tacked on gives us a family of results

OpenStudy (anonymous):

im seeing it

OpenStudy (amistre64):

u-sub would amount to:\[u=x^{1/2}\]\[du=\frac{1}{2x^{1/2}}dx\]\[2du=\frac{1}{x^{1/2}}dx\]and by substituting \[\int\frac{cos(x^{1/2})}{x^{1/2}}dx=>\int cos(u)\frac{1}{x^{1/2}}dx=>\int cos(u)2du\] therefore \[\int 2cos(u)~du\]

OpenStudy (anonymous):

\[\int\limits COS(X ^{1/2)}) * \frac{ 1 }{ x ^{1/2} }\]

OpenStudy (anonymous):

\[-2\sin \sqrt{x} + C\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!