Question

Find the distance d(P1, P2) between the points P1 and P2.
P1=(-5,1) P2=3,3)
d(P1, P2)=

Answer 1

you can plot the points to make a line
then the path from (-5,1) and (3,3) would for a triangle
so you can use pytagorean theorem for it
so it would be 8^2 + 2^2 = c^2
64 + 4 = c^2
c^2 = 68
c = sqrt(68) <--- distance

Answer 2

Ok, here is as far as I can get....d=\[\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^{2}} \]
\[x ^{1}=-5, y ^{1}=1, x ^{2}=3, y ^{2}=3\]

Answer 3

you can just plug in the points then x2 - x1 = 8
and y2 - y = 2

Answer 4

I still do not get it

Answer 5

I am not the brightest in this subject...sorry :(