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Solve r e^r=(1/2)^(t/80)
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\[e^r=\left(\frac12\right)^\frac{t}{80}\]
r = (-t/80) ln2
Okay that sort of helps... what is the numerical value of r?
if t be known.. r becomes specified... what is the t?
Well it doesn't give me t so lets just say it's 1
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okey then... we know that ln2=0.69314718056 so... r = -1/80 * 0.69314718056 right?
yes
got it right... thanks!
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