Question

Wondering if someone can talk me through this one:

Calculate the derivative using the appropriate rule or combination of rules.
f(x) = x(x^5 + 6)(x + 2)

Answer 1

first of all multiply x with any of the next two terms..

Answer 2

doesnt matter? ill do it with the second.

Answer 3

ok... you can multiply x to the pranthesis and also another mul. and then start for derivativing
or using chain rule.
i use second one

Answer 4

after distributing the x into one of the parentheses no chain rule, just product rule

Answer 5

so i got: (x^2+2x)(x^5+6)

Answer 6

f(x)=(x^6+6x) (x+2)
f'(x) = (6x^5 + 6) (1) + (1)(x^6+6x)
done :)

Answer 7

my answer is: 5x^7+10x^5+10x^6+12x

Answer 8

is that right?

Answer 9

you didn't take the derivative yet, you just distributed

Answer 10

explanation: (f(x)*g(x))' = f'(x)*g(x) + g'(x)*f(x)

Answer 11

you can take the derivative now though :)

Answer 12

there are many ways to do this problem...

Answer 13

i did the product rule of: (x^2+2x)(x^5+6)

Answer 14

ah okay, just that you didn't write out the middle step so I think you missed something

Answer 15

@TuringTest look as this..
f(x)=(x^6+6x) (x+2)
f'(x) = (6x^5 + 6) (1) + (1)(x^6+6x)
done :)
this is a reply you can see above... he/she hasn't explained anything...

Answer 16

@Kashan you clearly did not get my message to you, check your inbox

Answer 17

@yes I got it now... thanks...

Answer 18

so now i just add out (6x^5 + 6) (1) + (1)(x^6+6x)

Answer 19

so is my answer: x^6+6x^5+6x+6

Answer 20

do you see where that came from?

Answer 21

@bmelyk yes just solve it like simple algebraic expressions..

Answer 22

yes i see how he came up with that equation using the product rule after facotring in the x.

Answer 23

so yeah, now it's normal simplification

Answer 24

can you factor that anymore?

Answer 25

no its the answer...

Answer 26

ok thxxxxx :)

Answer 27

no problem.. :)