wanna get my answer checked please!

Find an equation of the tangent line at x = 0 for the given function.
y = 3e^x[sin(x)]

i had 1 as my final answer.

Question

wanna get my answer checked please!

Find an equation of the tangent line at x = 0 for the given function.
y = 3e^x[sin(x)]

i had 1 as my final answer.

anonymous · Answer

is the [sinx] a part of e power?

anonymous · Answer

no

anonymous · Answer

ok

anonymous · Answer

its just 3e to the power of x times sinx

anonymous · Answer

if i got the question correctly... the answer is 0.

anonymous · Answer

why

anonymous · Answer

$$3e ^{x}sinx$$

anonymous · Answer

yes... you want tan(0) by given function, right?

anonymous · Answer

no .. i just want the tangent line, so i get the derivative of the function
then i sub in 0 for x.

anonymous · Answer

so i used the product rule and got 3e^x (cosx+sinx)

anonymous · Answer

so when i subbed in zero i got 1.

anonymous · Answer

ahhh... yes i think u did well... i didn't got the question... sorry took ur time...

zepdrix · Answer

Sooo bem, that gives you the SLOPE of the tangent line at x=0, now we need to create an equation for the line passing through that point, with the given slope.

zepdrix · Answer

|dw:1351284126936:dw|
Hmmm I think you are suppose to get an answer of 3.
Check my work a sec, maybe you can tell me what you did differently.