Question

The formula A = 118e^(0.024t) models the population of a particular city, in thousands, t years after 1998. When will the population of the city reach 140 thousand?

A. 2008

B. 2005

C. 2006

D. 2007

Any kind of help is appreciated!

Answer 1

I think the answer is
C. 2006

Answer 2

how did you get 2006?

Answer 3

118e^(0.024t) switch t with 8 because 1998+8=2006
142.977 thousand.
In the year 2005 you get an answer under 140, so that leaves 2006 the closest year.

Answer 4

I would do
140= 118 e^(0.024t)
divide both sides by 118
140/118 = e^(0.024 t)
take the natural log ( abbreviated ln) of both sides
ln(140/118)= 0.024 t
divide both sides by 0.024
ln(140/118)/0.024 = t
t = 7.12 years

So the population reaches 140K in 1998+7.12 or 2005.12
so in the early part of 2005

Answer 5

is 2005.12 considered part of the year 2005 or 2006? remember the answer can only be 2005 or 2006, not in between.

Answer 6

2005.12 is 2006.. so C is the answer in my opinion.