Question

how do i solve for x the equation is 4x^+28x=176

Answer 1

Take 176 to the left side,
4x^2 + 28x - 176 = 0
Divide all the terms by 4
x^2 + 7x - 44 = 0
Then factor.

Answer 2

^what

Answer 3

subtract 176 from both sides, and then use the quadratic formula

Answer 4

whats the power

Answer 5

that is a lengthy one 11,4 as 11*-4=-44& 11-4=7
so x=11,-4:)

Answer 6

4x(squared) + 28x = 176

Answer 7

aperogalics--can you show me the work so I can understand the solution?

Answer 8

simple if the factorized form is(x-a)(x-b)=x^2-[a+b]x+ab i just use hit and trial method to find 2 nos whose sum or difference(depends upon product sign) is 7 and product is -44:)

Answer 9

4x^2 + 28x = 176
4x^2 + 28x - 176 = 0
4 (x^2 + 7x - 44) = 0
4 (x + 11) (x - 4) = 0
ignore the 4 out front and you get two equations, x + 11 = 0 and x - 4 = 0
therefore, x = -11 and x = 4

Answer 10

isellsani, all you have to do is divide both sides by 4, then you would have

(x + 11)(x - 4) = 0

Answer 11

I know that, was just avoiding another step as it's mundane.

Answer 12

It's not a mundane step, it is simply the next logical one.