What is the derivative of T(p)=87.97+34.96 ln p + 7.91 p^1/2
I got T'(p)=0 + 34.961 p ln^p-1 + 3.955p^-1/2
You are going to have to present the original function clearer. Is it T(p)=87.97+34.96*ln(p) + 7.91*p^1/2 ?
yes
okay, I am writing up a solution for you :)
thank you! I think I have it wrong
T'(p)=0+34.96/p+7.91(1.2)p^1.2-1 =34.96/p+9.492p^.2
^ @gomathi your original function is wrong. Which obviously led you to the wrong derivative
sorry the last termis P^1/2? then 34.96/p+7.91(1/2)p^1/2-1 34.96/p+3.95p^-1/2 34.96+3.95/p^1/2
the derivative of any ln is reciprocal of that function
Thank you! i always forget the rules for ln
therefore lnp is 1/p
hope you know constant p0wer of any variable is given by power *p^power minus one so p^1/2 is given by p ^1/2-1
yes
hope you follow the rules
i'll try :)
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