Ask your own question, for FREE!
Statistics 18 Online
OpenStudy (konradzuse):

Management for a chain of restaurants recorded the number of appetizers, X, ordered by tables dining. They observed that X had the following probability distribution. Value of X 0 1 2 3 or more Probability 0.60 0.35 0.04 0.01 Reference: Ref 9-7 The probability that a randomly chosen table orders at least one appetizer is A. 0.35. B. 0.39. C. 0.40. D. none of the above.

OpenStudy (konradzuse):

Same thing... 0.01 + 0.35 + 0.04 = .40 or 1-0.6 = 0.40.

OpenStudy (konradzuse):

@CliffSedge

OpenStudy (anonymous):

I choose a card at random from a well-shuffled deck of 54 cards (the usual 52 cards plus two jokers). There is a 13/54 probability that the card chosen is a spade, a 13/54 probability that the card is a heart, a 13/54 probability that the card is a diamond, and a 13/54 probability that the card is a club. Both spades and clubs are black cards, while hearts and diamonds are red. In addition, one of the jokers is a black card and the other joker, a red card. Reference: Ref 10-4 What is the probability that the card chosen is red? A. .25 B. .50 C. .75 D. 1.00

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!