HELP PRECAL PROBLEM??!!?
A. -1
B. 27
C. There isn't enough information to answer the question
D. 29
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OpenStudy (anonymous):
OpenStudy (anonymous):
expand the log, get
\[5\log(A)+2\log(C)-6\log(D)\] then plug in the numbers
OpenStudy (anonymous):
using two facts
\[\log(AB)=\log(A)+\log(B)\]and
\[\log(A^n)=n\log(A)\]
OpenStudy (anonymous):
i'm so confused
OpenStudy (anonymous):
well it is late, time to stop doing math
but the idea is this
if for example \(\log(A)=5\) and \(\log(B)=3\) then
\[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+3\log(B)\]
\[=4\times 5+3\times 2\]
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OpenStudy (anonymous):
will this one be 5x7/2?
OpenStudy (anonymous):
oops i meant
\[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+2\log(B)\]
\[=4\times 5+2\times 3\]
OpenStudy (anonymous):
no, plug in the numbers you know here
\[5\log(A)+2\log(C)-6\log(D)\]
OpenStudy (anonymous):
5log(5)+2log(7)−6log(2)
OpenStudy (anonymous):
replace \(\log(A)\) by 5
\(\log(C)\) by 7
\(\log(D)\) by 2
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OpenStudy (anonymous):
not the log of 5, just the number 5
OpenStudy (anonymous):
5+7-2?
OpenStudy (anonymous):
not \[5log(5)+2log(7)−6log(2)\] but rather
\[5\times 5+2\times 7-6\times 2\]
OpenStudy (anonymous):
this one is dividing tho, so wouldn't it be different?
OpenStudy (anonymous):
oh ok i see now
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OpenStudy (anonymous):
that is the reason for the subtraction
OpenStudy (anonymous):
25+14-12?
OpenStudy (anonymous):
\[\log(\frac{A}{B})=\log(A)-\log(B)\]
OpenStudy (anonymous):
yeah i guess so
OpenStudy (anonymous):
thanks!
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