HELP PRECAL PROBLEM??!!? A. -1 B. 27 C. There isn't enough information to answer the question D. 29
expand the log, get \[5\log(A)+2\log(C)-6\log(D)\] then plug in the numbers
using two facts \[\log(AB)=\log(A)+\log(B)\]and \[\log(A^n)=n\log(A)\]
i'm so confused
well it is late, time to stop doing math but the idea is this if for example \(\log(A)=5\) and \(\log(B)=3\) then \[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+3\log(B)\] \[=4\times 5+3\times 2\]
will this one be 5x7/2?
oops i meant \[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+2\log(B)\] \[=4\times 5+2\times 3\]
no, plug in the numbers you know here \[5\log(A)+2\log(C)-6\log(D)\]
5log(5)+2log(7)−6log(2)
replace \(\log(A)\) by 5 \(\log(C)\) by 7 \(\log(D)\) by 2
not the log of 5, just the number 5
5+7-2?
not \[5log(5)+2log(7)−6log(2)\] but rather \[5\times 5+2\times 7-6\times 2\]
this one is dividing tho, so wouldn't it be different?
oh ok i see now
that is the reason for the subtraction
25+14-12?
\[\log(\frac{A}{B})=\log(A)-\log(B)\]
yeah i guess so
thanks!
yw
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