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Mathematics 19 Online
OpenStudy (anonymous):

HELP PRECAL PROBLEM??!!? A. -1 B. 27 C. There isn't enough information to answer the question D. 29

OpenStudy (anonymous):

OpenStudy (anonymous):

expand the log, get \[5\log(A)+2\log(C)-6\log(D)\] then plug in the numbers

OpenStudy (anonymous):

using two facts \[\log(AB)=\log(A)+\log(B)\]and \[\log(A^n)=n\log(A)\]

OpenStudy (anonymous):

i'm so confused

OpenStudy (anonymous):

well it is late, time to stop doing math but the idea is this if for example \(\log(A)=5\) and \(\log(B)=3\) then \[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+3\log(B)\] \[=4\times 5+3\times 2\]

OpenStudy (anonymous):

will this one be 5x7/2?

OpenStudy (anonymous):

oops i meant \[\log(A^4B^2)=\log(A^4)+\log(B^2)=4\log(A)+2\log(B)\] \[=4\times 5+2\times 3\]

OpenStudy (anonymous):

no, plug in the numbers you know here \[5\log(A)+2\log(C)-6\log(D)\]

OpenStudy (anonymous):

5log(5)+2log(7)−6log(2)

OpenStudy (anonymous):

replace \(\log(A)\) by 5 \(\log(C)\) by 7 \(\log(D)\) by 2

OpenStudy (anonymous):

not the log of 5, just the number 5

OpenStudy (anonymous):

5+7-2?

OpenStudy (anonymous):

not \[5log(5)+2log(7)−6log(2)\] but rather \[5\times 5+2\times 7-6\times 2\]

OpenStudy (anonymous):

this one is dividing tho, so wouldn't it be different?

OpenStudy (anonymous):

oh ok i see now

OpenStudy (anonymous):

that is the reason for the subtraction

OpenStudy (anonymous):

25+14-12?

OpenStudy (anonymous):

\[\log(\frac{A}{B})=\log(A)-\log(B)\]

OpenStudy (anonymous):

yeah i guess so

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

yw

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