The average speed for a journey is the distance covered divided by the time taken [...] More in reply. Having issues with how to deduce and writing the equation for the second half (first half is solved)
One journey is completed by travelling for the first half of the time at speed \[v _{1}\]and the second half at speed \[v _{2}\]The average Speed these two are \[v _{a} = \frac{v _{1} + v _{2}}{2}\] Another journey is complete by travelling at the speed \[v _{1}\]for half the distance and at speed \[v _{1}\] Find the average speed \[v _{b}\]for the journey in terms of \[v _{1}\]and \[v _{2}\]Deduce that a journey is complete by travelling at two different speeds for equal distances will take longer than the same journey completed at the same two speeds for equal times.
In terms of finding the average speed of Vb: d = 2(v1)(t1) = 2(v2)(t2) t1 = d/(2v1), t2 = d/(2v2) d = (va)(t1 + t2) d = (va)[d/(2v1) + d/(2v2)] 1/(va) = 1/(2v1) + 1/(2v2) va = 2(v1)(v2) / (v1 + v2)
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