Question

An easy way to memorize the differentiations of trig functions?

Answer 1

Can this kinda chain help?
sin(x)
|
cos(x)
|
-sin(x)
|
-cos(x)
|
SIN(X)

Answer 2

there is no easy way. it comes with enough practice and problems. Thats how i got them. sin=cos, cos=-sin, tan = sec^2, sec = sec*tan...thats what i know...the other 2 dont get used that often. the chain/circular reference does kinda work

Answer 3

Yeah, but where's the tan(x)?

Answer 4

And the hyperbolic ones?

Answer 5

cos = -sin ^

Answer 6

ive never had to use the hyperbolic ones, and the inverse ones (i.e. sin^-1) are very difficult to memorize because they all look the same

Answer 7

Hmm... okay.

Answer 8

But still, is there a way to memorize all of this stuff?

Answer 9

do lots of problems. Eventually you'll memorize them because you see them so often

Answer 10

How about the sec and cosec?

Answer 11

sec = sec*tan, csc = -cscx*cotx. theyre basically opposites, so if you know sec, you can get csc

Answer 12

You can refer to such thing, bind sin and cos, tan and sec, cot and cosec. They are together in different formulas.

Answer 13

yup practice

Answer 14

I would really like to know this too. Memorizing diff trig variables.

Answer 15

just remember: derivative of a cofunction is negative

i.e.

d/dx of cos x is -sinx

d/dx of csc x is -csc x cot x

d/dx of cot x is -csc^2 x

Answer 16

would help alot actually

Answer 17

and most importantly: hate math

Answer 18

I've never had to memorize them. After doing them a few times, you just know them. I'm only speaking for myself, but I just know all the differentiation rules, trig identities by heart. Actually pretty much any formula, I've never had to really memorize, but rather just understand the justification behind them. I can't explain it but I pretty much know any mathematical formula, rules, etc, by heart. I guess that's why I love MATH!

Answer 19

Hmm. I'd try that way. Thanks @calculusfunctions