Find the equation of the line with the given properties. Express the equation in general form or slope-intercept form.
perpendicular to the line 2x+y=3; contains the point (-2,6)
The equation of the line is____________
Simplify your answer. Type answer in general form or slope-intercept form.
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OpenStudy (anonymous):
start by solving for y
OpenStudy (calculusfunctions):
If given the equation of a line in the form Ax + By = C, then the slope of the line perpendicular to this line is given by\[m =\frac{ B }{ A }\]
OpenStudy (anonymous):
y=2x+3
y-6=1/2x+2
I got this part
OpenStudy (anonymous):
slow down for a minute
OpenStudy (calculusfunctions):
Try again.
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OpenStudy (anonymous):
first you need to find the inverse of your equation
The gradient of the new line is -(1/grad of old line).
OpenStudy (anonymous):
gradient=slope
OpenStudy (anonymous):
@malibugranprix2000 do you understand or do you need me to explain it more?
OpenStudy (anonymous):
I think I need help, please.
OpenStudy (anonymous):
ok so how would you get y by itself?
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OpenStudy (anonymous):
by moving the 2x+3
OpenStudy (anonymous):
but if 2x is positive you need to subtract it to the other side so you would get y=-2x+3
OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok so what is your slope in this equation?
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
ok now the slope of the new line is -(1/slope)
OpenStudy (anonymous):
just let me know if you dont understand where i am going and i will help you through it
OpenStudy (anonymous):
so what is the slope?
OpenStudy (anonymous):
the slope of the new line is -(1/(-2))
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OpenStudy (anonymous):
oh I see
OpenStudy (anonymous):
so that simplified turns out to be what?
OpenStudy (anonymous):
is it 1/2
OpenStudy (anonymous):
ok so if we put that into the equation we get y=(1/2)x+b correct
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
in the question they also gave you an x and y value plug those into the equation
OpenStudy (anonymous):
do you understand how to do that?
OpenStudy (anonymous):
@malibugranprix2000 ?
OpenStudy (anonymous):
that is plugged in as x1 and y1
OpenStudy (anonymous):
plug it into the equation i just gave you
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OpenStudy (anonymous):
6=-2x+3
OpenStudy (anonymous):
leave b alone and change x instead
OpenStudy (anonymous):
and we are entering that into y=(1/2)x+b this equation
OpenStudy (anonymous):
@malibugranprix2000 come on i want to get to bed not trying to be mean or anything
OpenStudy (anonymous):
oh I am sorry you can go thats fine.
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OpenStudy (anonymous):
no i want to help we can get it done in 5 min i you just bear with me
OpenStudy (anonymous):
so we have 6=(1/2)(-2)+b right
OpenStudy (anonymous):
right
OpenStudy (anonymous):
6=-1+b
OpenStudy (anonymous):
ok now get b by itself
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OpenStudy (anonymous):
so I am not sure b=-1+6?
OpenStudy (anonymous):
you need to add one to both sides
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
6+1=-1+6+1
OpenStudy (anonymous):
because you are adding the same thing to both side they cancel out meaning that the equation is still equal
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OpenStudy (anonymous):
oh so its 7=-5+1
OpenStudy (anonymous):
sorry 6+1=-1+b+1
OpenStudy (anonymous):
so the -1 and 1 cancel out and leave b by itself
OpenStudy (anonymous):
7=-1+b
OpenStudy (anonymous):
nope its just 7=b
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OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
understand how that works?
OpenStudy (anonymous):
yes, thanks a lot
OpenStudy (anonymous):
now take the b that we just found and plug it into our new equation y=(1/2)x+b
OpenStudy (anonymous):
y=(1/2)x+7
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