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Physics 18 Online
OpenStudy (anonymous):

please help. thanks:)

OpenStudy (anonymous):

http://screencast.com/t/v4agnO7Pf

OpenStudy (anonymous):

@ParthKohli @ilikephysics2 @Hero @hartnn

OpenStudy (anonymous):

f=ma f=m(v/t) 60=30(v/0.50)

OpenStudy (anonymous):

a= v-u/t

OpenStudy (anonymous):

you r right a=change in vel per time

OpenStudy (anonymous):

f=m((v-u)/t)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

wt answer did u get

OpenStudy (anonymous):

i did not solve it

OpenStudy (anonymous):

u=3 met/sec

OpenStudy (anonymous):

yh tell me the answer

OpenStudy (anonymous):

2m/s

OpenStudy (anonymous):

cn u show the working

OpenStudy (anonymous):

f=-60 as it is retarding force f/m=(v-u)/t -60/30=(v-3)/0.50 -2*0.50=v-3 -1+3=v v=2m/s

OpenStudy (anonymous):

thanks alot :)

OpenStudy (anonymous):

welcome

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