Using the given zero, find one other zero of f(x). Explain the process you used to find your solution. 1 - 2i is a zero of f(x) = x4 - 2x3 + 6x2 - 2x + 5.
there is a theorem that states 'if a+bi is a zero, then a-bi is also a zero of a function with real co-eff' so if 1-2i is a zero, 1+2i is also a zero of f(x), let me find out the name of that theorem Conjugate Pair Theorem: If a polynomial has real coefficients then any complex zeros occur in complex conjugate pairs. That is, if a + bi is a zero then so is a – bi, where a and b are real numbers.
alright, so this is what you sent me
yes.
alright so.
Conjugate Pair Theorem: If a polynomial has real coefficients then any complex zeros occur in complex conjugate pairs. That is, if a + bi is a zero then so is a – bi, where a and b are real numbers. so if 1-2i is one of the zeros, then according to Conjugate Pair Theorem, 1+2i is another zero
okay
sooo now what
the question asked for other zero, and u got it as 1+2i, using a theorem.....
oh okay. so thats it?
do i have to plug that in or anything
i guess so, i don't see anything to work out here....
do u have s0lved example of a similar question ?
no
plugging in 1-2i is of no use.
ookay
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