Mathematics
21 Online
OpenStudy (anonymous):
solve the tree roots
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OpenStudy (anonymous):
\[ \sqrt{2x^2+x+5}+\sqrt{x^2+x+1}=\sqrt{x^2-3x+13}\]
OpenStudy (hba):
Squaring both sides :)
OpenStudy (anonymous):
that is the last option do you see any relationship
OpenStudy (hba):
Well i do not recommend it to do that way
OpenStudy (anonymous):
\[3x^2+2x+6+2\sqrt{(2x^2+x+5)(x^2+x+1)}=x^2-3x+13\]
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OpenStudy (hba):
just because of the complications :)
OpenStudy (anonymous):
\[2x^2+5x-9+2\sqrt{roots}=0\]
OpenStudy (hba):
no keep 2underroot on one side and take the rest on one side and then apply squaring both sides again
OpenStudy (hba):
\[2\sqrt{roots}=-2x^2-5x+9\]
OpenStudy (anonymous):
lol i see that adding theroots gives the number outside
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OpenStudy (anonymous):
a relationxip
OpenStudy (anonymous):
\[-(p+q)=2\sqrt{pq}\]
OpenStudy (anonymous):
\[p^2+2pq+q^2=4pq\]
\[p^2-2pq+q^2=0\]
OpenStudy (anonymous):
\[(p-q)^2=0\]
OpenStudy (anonymous):
p=q
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OpenStudy (anonymous):
\[x^2+x+1=x^2-3x+13\]
OpenStudy (anonymous):
\[x=3\]
OpenStudy (anonymous):
is this correct
OpenStudy (cwrw238):
yes
OpenStudy (anonymous):
ithink there is a problem
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OpenStudy (anonymous):
i ignored x^2-13x+13 on the right
OpenStudy (cwrw238):
-13x?
OpenStudy (anonymous):
\[-2\sqrt{roots}=2x^2+5x-9\]
sum of roots dnt give number out side
OpenStudy (anonymous):
no i meant -3x
OpenStudy (anonymous):
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OpenStudy (anonymous):
unsorted
OpenStudy (anonymous):
@hartnn can you see the mistake
hartnn (hartnn):
its not x=3, i saw your mistake, but i don't have any better method to come up with, thats why i was silent