OpenStudy (anonymous):

solve the tree roots

5 years ago
OpenStudy (anonymous):

\[ \sqrt{2x^2+x+5}+\sqrt{x^2+x+1}=\sqrt{x^2-3x+13}\]

5 years ago
OpenStudy (hba):

Squaring both sides :)

5 years ago
OpenStudy (anonymous):

that is the last option do you see any relationship

5 years ago
OpenStudy (hba):

Well i do not recommend it to do that way

5 years ago
OpenStudy (anonymous):

\[3x^2+2x+6+2\sqrt{(2x^2+x+5)(x^2+x+1)}=x^2-3x+13\]

5 years ago
OpenStudy (hba):

just because of the complications :)

5 years ago
OpenStudy (anonymous):

\[2x^2+5x-9+2\sqrt{roots}=0\]

5 years ago
OpenStudy (hba):

no keep 2underroot on one side and take the rest on one side and then apply squaring both sides again

5 years ago
OpenStudy (hba):

\[2\sqrt{roots}=-2x^2-5x+9\]

5 years ago
OpenStudy (anonymous):

lol i see that adding theroots gives the number outside

5 years ago
OpenStudy (anonymous):

a relationxip

5 years ago
OpenStudy (anonymous):

\[-(p+q)=2\sqrt{pq}\]

5 years ago
OpenStudy (anonymous):

\[p^2+2pq+q^2=4pq\] \[p^2-2pq+q^2=0\]

5 years ago
OpenStudy (anonymous):

\[(p-q)^2=0\]

5 years ago
OpenStudy (anonymous):

p=q

5 years ago
OpenStudy (anonymous):

\[x^2+x+1=x^2-3x+13\]

5 years ago
OpenStudy (anonymous):

\[x=3\]

5 years ago
OpenStudy (anonymous):

is this correct

5 years ago
OpenStudy (cwrw238):

yes

5 years ago
OpenStudy (anonymous):

ithink there is a problem

5 years ago
OpenStudy (anonymous):

i ignored x^2-13x+13 on the right

5 years ago
OpenStudy (cwrw238):

-13x?

5 years ago
OpenStudy (anonymous):

\[-2\sqrt{roots}=2x^2+5x-9\] sum of roots dnt give number out side

5 years ago
OpenStudy (anonymous):

no i meant -3x

5 years ago
OpenStudy (anonymous):

5 years ago
OpenStudy (anonymous):

unsorted

5 years ago
OpenStudy (anonymous):

@hartnn can you see the mistake

5 years ago
hartnn (hartnn):

its not x=3, i saw your mistake, but i don't have any better method to come up with, thats why i was silent

5 years ago
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