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OpenStudy (ksaimouli):
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
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OpenStudy (anonymous):
g = G M/((R+h)^2) where h is 3.59 10^7 m
OpenStudy (anonymous):
G is gravity constanta, and M is mass of earth..,
OpenStudy (ksaimouli):
but the formula |dw:1351351359708:dw|
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