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OpenStudy (ksaimouli):

Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

OpenStudy (anonymous):

g = G M/((R+h)^2) where h is 3.59 10^7 m

OpenStudy (anonymous):

G is gravity constanta, and M is mass of earth..,

OpenStudy (ksaimouli):

but the formula |dw:1351351359708:dw|

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