##Can someone explains the different outcome if I ##change 0.1 to 0.5 at line " ans = ans + 0.1"
## while x = 8 ?

x = float(raw_input('Enter a number:'))
ans = 0.0
print type (ans)
while ans*ans*ans

Question

##Can someone explains the different outcome if I ##change 0.1 to 0.5 at line " ans = ans + 0.1" 
## while x = 8 ?

x = float(raw_input('Enter a number:'))
ans = 0.0
print type (ans)
while ans*ans*ans < abs(x):
     ans = ans+0.1
     ## ans = ans +0.5
     print ans
if ans*ans*ans != abs(x):
     print x , ' is not a perfect cube'
else:
     if x<0:
          ans = -ans
     print 'Cube root of ', str(x), 'is' , str(ans)

anonymous · Answer

I'm slightly confused.  A perfect cube should had a cube root that is an integer, so why are you using a float here?
If you change the line to ans = ans + 0.5, then you're going to be checking less cube roots.  For example you wont check 0.1 or 0.2 or 0.3 or 0.4.  Thus you have a greater probability of missing the cube root.

anonymous · Answer

There are better ways of finding the cube root, by the way.  Like using Newton's root finding method.

anonymous · Answer

Also, because you are checking fewer times (at a greater interval), that will impact the accuracy of your program's result.

harsimran_hs4 · Answer

please use the pasting websites to paste your code http://pastebin.com/ http://dpaste.com/ definitely for the computation of a perfect cube you just need to increase the ans by 1 also you might be confused that you should not get 'not a perfect cube' , it is because of float point error.(the way computer perceives the number may be a little different than you may think)