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Mathematics 18 Online
OpenStudy (anonymous):

what does cos^-1 mean?

OpenStudy (anonymous):

if cos (x) = adjacent/hypotenuse, then x = cos^-1(adjacent/hypotenuse)

OpenStudy (calculusfunctions):

\[\cos ^{-1}x\]means the inverse of cosine.

OpenStudy (calculusfunctions):

Suppose that\[cosy =x\]then\[y =\cos ^{-1}x\]In other words if the cosine of an angle is x, then the inverse cosine of x is the angle y.

OpenStudy (anonymous):

yes but why does it change to cos^-1.... wouldnt htat be the same as 1/cos ?

OpenStudy (anonymous):

no, thats just the notation for it. 1/cosine is actually secant. two different functions. if its cos^-1(x) its the inverse, and if its (cos(x))^-1 then its secant

OpenStudy (calculusfunctions):

Example: If\[\cos \theta \approx 0.7071\]then\[\theta = \cos ^{-1}(0.7071)\]Therefore\[\theta =45° \]

OpenStudy (anonymous):

isn't that the same as arccos

OpenStudy (anonymous):

\(^{-1}\) is notation for inverse. It isn't always multiplicative inverse (reciprocal).

OpenStudy (calculusfunctions):

Yes correct!\[\cos ^{-1}x =arc cosx\]

OpenStudy (anonymous):

I always preferred the name, "arc-cosine" because it does tell you the arc of the central angle.

OpenStudy (calculusfunctions):

Yes, I believe I already explained that it means inverse, elegantly.

OpenStudy (calculusfunctions):

That is true, it is the arc of a central angle.

OpenStudy (anonymous):

LOL, yes, very elegantly indeed.

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