Question

Question is going to be attached.....

Answer 1

y=2x^2 is at the center origin(0,0)
parabola y=2x^2 -1 ,vertex at (0,-1) shifted y=-1
A). y=2(x-4)^2 -1 ,parabola shifted to the right,vertex at (4,-1) shifted to the right x=4,y=-1
can you try the other 3?

Answer 2

B) y=2(x+4)^2 -1,parabola shifted to the left,vertex at (-4,-1) shifted to the left x=-4,y=-1

Answer 3

try the other two @ malibugranprix2000

Answer 4

I am trying to look at what you wrote and I am figuring it out.

Answer 5

ok take your time

Answer 6

I am stuck on how to figure this out.

Answer 7

ok lets figure out C)

Answer 8

on A) the parabola y=2(x-4)^2 -1 , shifted to the right,vertex at (4,-1) shifted to the right x=4,y=-1,

the vertex on A) is at V(4,-1),,
but on C) you wanted it to be V(x,y)=V(4,+1) to be lifted up to y=1
therefore just change y yo be y=+1 , and A) becomes

y=2(x-4)^2 +1

Answer 9

notice
if you want to be on the right side you use (x-4)
if you want to be on the left side you use (x+4)
also
if you want to be on the top side you just add y
if you want to be on the bottom side you just subtract y

Answer 10

So is A the answer to this problem.

Answer 11

hmm you talking about y=2(x+4)^2 -1 ?

Answer 12

for this one (x+4) and -1
you moved the graph to the left side and brought down to y=-1
thats B)

Answer 13

hold on wait a minute, i just noticed the graph of A), C) and D) are so narrow but on B) its wider... so the graph should be either on A), C) and D) not B)

Answer 14

so instead of B), y=2(x+4)^2 -1 , its D)

Answer 15

both B) and D) looks the same but different on narrow or wider parabola

Answer 16

any question?

Answer 17

um I realized it looks smaller I can give the bigger picture

Answer 18

D is the right answer. this link might help for future reference
http://jwilson.coe.uga.edu/emt668/EMAT6680.Folders/Barron/Write-ups/Assignment%202/Barronwrite-up2.html

Answer 19

thanks mark_o and etemplin