Question

Someone please check.
q+12-2(q-22)>0
q+10q-220>0
11q(-220+220)>0
11q>220
q>20

Answer 1

where do you get 10q from?

Answer 2

12-2, then I distributed by parenthesis

Answer 3

Is that wrong NickR?

Answer 4

you need to distribute first

Answer 5

\[q+12-2(q-22)>0\]

Answer 6

That's the start, right?

Answer 7

@cbm (just making a notification pop up :P )

Answer 8

i think you made a mistake there
q+12-2(q-22)>0
q+12-2q+44 >0
-q +56 >0
-q > -56
q>56

Answer 9

sorry q<56

Answer 10

I agree with jayz657's work.
Any questions, @cbm ?

Answer 11

Thank ya'll so much! I was reworking it. Yep, once I distributed I got the same answer. The sign at the end changed right? From > to <

Answer 12

I wish you could give more than one best response

Answer 13

Yep! Because you multiplied or divided by a negative!

Answer 14

@theEric thanks!

Answer 15

My pleasure. I'm glad you got it worked out :) Good luck with any more you have to do!

Answer 16

Thanks, I'm struggling with one more now trying to set up an inequality.

Answer 17

You can ask it here or in another question. I have time if you'd like a hand. Algebra like this can be hard at first.

Answer 18

Ok, it will take me a minute to type it. Thanks for your help. Yes, I'm too old to learn this stuff.

Answer 19

Haha, no such thing. It might just require some thinking and rethinking, right? Maybe thinking in a different light!
I started thinking about counting cookies/blocks again before so the numbers meant something.

Answer 20

And take your time!

Answer 21

Your making a rectangular patio that is 10ft wide and 20ft long, using square pavers that have an area of 0.81 sq ft, what is the # of pavers u will need? Write and solve an inequality to find the answer.

Answer 22

Lol, I'm trying. I thought I had equations but not the fractions

Answer 23

would it be like (10x20).81=p

Answer 24

idn

Answer 25

The first step is always understanding the problem. Then we move on.. So I have a quick question... Each "paver" is .81 square feet, and we need to know how many of the will fit in our 10 foot by 20 foot area?

Answer 26

Yep, thats the question.

Answer 27

Alright! Then (10*20) is definately your area of the patio. And you wanna see how many .81 area portions will fit into that. How many times does .81 go into (10*20) is the question to get you to your answer. That's a division thing.

Answer 28

I got 246,9 so P≥246.9

Answer 29

That's just one way to look at it. There's another way in which you build the equation and solve..

I got the same number after rounding. Is this supposed to be inequality?

Answer 30

I'm not sure if I'm writing the inequality right or not
(10ftx20ft)/.81=p

Answer 31

Yes, it's supposed to be an inequality

Answer 32

That's what I would do to!

Answer 33

To me it works and gives the answer when you work it.

Answer 34

I don't see why it would be inequality! There must be something I'm not thinking of.. I thought it would want an exact number...You want so many pavers.... OR! Do you want at least so many pavers? Meaning that many or more?

Answer 35

Do you want me to create a problem so I can give you a medal? I'm not sure what the medal do.

Answer 36

I was trying to figure out why it want come out to a whole number also unless it's ≥

Answer 37

They're just sort of recognition you can count. I'm not worried about it. Thanks though!

Answer 38

Yeah, I think maybe that's the idea of it.. why they want inequality.. Although you'd think rounding it up to 247 would be good enough! Maybe the question was just not appropriate for this subject!

Answer 39

Oh, ok thanks! Maybe (10x20)/.81≥p

Answer 40

I would say \[p\ge 246.0\]

Answer 41

You would want more pavers rather than less. At least you get your patio done that way :P

Answer 42

LOL, that's the truth.

Answer 43

Pavers area things should be greater than or equal to the patio area... to get the patio done :P Yeah!

Answer 44

Using just that sentence, you can set up the inequality.
\[p_{NumberOfPavers}\ge A_{PatioArea}\]

Answer 45

I've been trying everything to get an even number. I don't understand why it would be a decimal. I tried breaking it up into inches, etc. Thanks again for your help.

Answer 46

It might just not come out to be an even number. It happens. We could solve it to be a fraction instead of a decimal. With fractions, your always exact (no rounding).

Answer 47

I have five cookies to share between us. How many can we each have? 2.5. Books don't always make problems come out to nice numbers either..

Answer 48

So maybe that's the case here.

Answer 49

true, I hope so.

Answer 50

Same. Good luck with that! If you solve it as a fraction, note that .81 = 81/100.

Answer 51

alright, Thanks again!!

Answer 52

\[\frac{10*20}{.81}=\frac{10*20}{\frac{81}{100}}\]
Np!

Answer 53

:)

Answer 54

Just in case... From there, it's
\[\frac{10*20*100}{81}=\frac{20000}{81}=246\frac{74}{81}\]

Answer 55

Yep, that works good or at least it looks better. I figured I could write the equation as
(p)x0.81≥200. I'm still working it to see if it will work.

Answer 56

That's great, and it was the other way I would think of the equation to solve!

Answer 57

And you don't have to change the sign because 0.81 is not negative.