Mathematics
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OpenStudy (anonymous):
Oh my gosh my study time is almost up 2 more questions to go! Muaha, Help me please :3
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OpenStudy (anonymous):
hartnn (hartnn):
can u find slope of y=1/2 x + 1 ?
OpenStudy (anonymous):
1/2
hartnn (hartnn):
yes, and slope of parallel lines are ..... ?
OpenStudy (anonymous):
the same ? 0.0
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hartnn (hartnn):
yes, so u have slope of your line as m=1/2
OpenStudy (anonymous):
yus
hartnn (hartnn):
now it passes through 12,15
u know the slope point form of equation of line ?
OpenStudy (anonymous):
i do but im sleepy so its not coming to me at the moment
hartnn (hartnn):
(y-y1) = m (x-x1)
here, x1= 12, y1 = 15
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OpenStudy (anonymous):
(y-15)=m(x-12)
hartnn (hartnn):
u already had m. put that also
then isolate y
OpenStudy (anonymous):
y=1/2x+9?
hartnn (hartnn):
yes :)
OpenStudy (anonymous):
so which is perpendicular?
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hartnn (hartnn):
now slope of perpendicular line is..?
OpenStudy (anonymous):
>.> jihx
OpenStudy (anonymous):
idk >.<
hartnn (hartnn):
negative reciprocal.
so take reciprocal of 1/2 , what u get
then multiply it by -1
hartnn (hartnn):
reciprocal of 1/2 is ?
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OpenStudy (anonymous):
2/1
hartnn (hartnn):
and multiplying 2 with -1 will give u ?
OpenStudy (anonymous):
you get -2
hartnn (hartnn):
yes
hartnn (hartnn):
so slope = -2
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hartnn (hartnn):
which option ?>
OpenStudy (anonymous):
B right?
hartnn (hartnn):
yup :)
OpenStudy (anonymous):
Omahgerd. I has one more :3
hartnn (hartnn):
okay :)
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OpenStudy (anonymous):
OpenStudy (anonymous):
i only has 5 minutes before someone else needs computer :0
hartnn (hartnn):
this can't be solved in 5 min.
hartnn (hartnn):
Distance between points (x1,y1) and (x2,y2) is
\(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)
OpenStudy (anonymous):
sorry i got disconnected
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hartnn (hartnn):
me too :\
OpenStudy (anonymous):
Well. looks like ill have to get off in a minute. dont even think ill have time to attempt problem :(
OpenStudy (anonymous):
I just wanted to say thank you for all of your help. You've been on like every single problem of mine xD