Question

+ & - Radical Expressions help please!!! (give me a moment to insert the equation)

Answer 1

\[\LARGE 4\sqrt{2} + 7\sqrt{2} - 3\sqrt{2}\]

ANSWER CHOICES:
A) \[\Large 2\sqrt{8}\]
B) \[\Large 8\sqrt{2}\]
C) \[\Large 8\sqrt{6}\]
D) \[\Large 6\sqrt{8}\]

Answer 2

Can somebody please tell me how to do this?

Answer 3

\[4x+7x-3x=?\]

Answer 4

just the same as the algebra question "combine like terms"

Answer 5

I still don't understand...

Answer 6

@jim_thompson5910 Can you help me?? :)

Answer 7

What do you get when you add 2x to 3x (ie how how do you combine these like terms)?

Answer 8

5x?

Answer 9

how did you do that

Answer 10

I added the 2 & 3 & then put the x back on.

Answer 11

good, that's exactly what satellite73 is saying and exactly what you do

so for instance, if you wanted to add \[\Large 5\sqrt{3}+7\sqrt{3}\], you just add the numbers in front of the square root of 3 (ignore the square root of 3) to get

5+7 = 12

Then you tack the square root of 3 back on the result you just got to say

\[\Large 5\sqrt{3}+7\sqrt{3}=12\sqrt{3}\]

Answer 12

So what do you get when you simplify

\[\Large 4\sqrt{2} + 7\sqrt{2} - 3\sqrt{2}\]

Answer 13

\[\LARGE 8\sqrt{2}\] ?? :)

Answer 14

you nailed it

Answer 15

that's all there is to it

Answer 16

Thank you :)

Answer 17

yw

Answer 18

@jim_thompson5910
\[\Large (12\sqrt{5} - 7\sqrt{7}) + (\sqrt{5} - 7\sqrt{7})\]

I tried to do the same thing with this one but I got confused... Help, please?

Answer 19

well this time, you can only do it for the like terms

Answer 20

\[\Large (12\sqrt{5} - 7\sqrt{7}) + (6\sqrt{5} - 7\sqrt{7})\]

Answer 21

Corrected^

Answer 22

for instance, you cannot add the numbers in front of the sqrt(5) and sqrt(7)

Answer 23

the numbers in front of the sqrt(5) are...???

Answer 24

12 & 6

Answer 25

Would I add them?

Answer 26

so they add to 18, which means that the final result for the sqrt(5) term is

\[\Large 12\sqrt{5}+6\sqrt{5} = 18\sqrt{5}\]

Answer 27

yes you would

Answer 28

And so it would be 18sqrrt5 & that's it b/c the 7's cancel each other out?

Answer 29

Cos they equal zero?

Answer 30

no, not quite

Answer 31

-7 + -7 isn't 0

Answer 32

oh... it's -14

Answer 33

yes

Answer 34

so \[\LARGE 18\sqrt{5} and -14\sqrt{7}\] ??

Answer 35

then you just write them as one expression, so the answer would be

\[\Large 18\sqrt{5} -14\sqrt{7}\]

you can't combine these because they are not like terms.

Answer 36

oh, okay! Thank you :)

Answer 37

np

Answer 38

Would
\[\Large \sqrt{10} \times \sqrt{8}\]
be \[\Large \sqrt{80}\] ??

Answer 39

yes and you can simplify that

Answer 40

How?

Answer 41

Wait... to \[\Large 4\sqrt{5} \] ?

Answer 42

you got it

Answer 43

do you know how to get that?

Answer 44

The same way you taught me to simplify the other day :)

Answer 45

ok great, just checking

Answer 46

Whoah! How do I do this one?
\[\LARGE \sqrt{5}(8 + 3\sqrt{6})\]

Answer 47

@jim_thompson5910

Answer 48

treat sqrt(5) just like any number and distribute it through

Answer 49

so 8*5 is 40 5*3=15 5*6 = 30

Answer 50

kinda, but you multiply sqrt(5) by 8 and sqrt(5) by 3*sqrt(6)

Answer 51

I'm confused..

Answer 52

sqrt(5) times 8 = ??

Answer 53

... 17-ish?? Idk.

Answer 54

no, it's just 8*sqrt(5)

Answer 55

oh.... okay ha

Answer 56

sqrt(5) times 3*sqrt(6) = ???

Answer 57

Idk...