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OpenStudy (anonymous):
A force F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a =5.0N/m^2 . Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.
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OpenStudy (anonymous):
F = ax^2 plug in 0, and 6 which gives you 180J and 0J, subtract them and you get 180J
OpenStudy (anonymous):
W=F(d) = 180(6) = 1080 watts
OpenStudy (anonymous):
lol for reals?
OpenStudy (anonymous):
Pretty sure broski
OpenStudy (anonymous):
did you finish the whole thing?
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OpenStudy (anonymous):
Currently on #4
OpenStudy (anonymous):
Wow! Your gettin it done early!
OpenStudy (anonymous):
;) go on skype and we can talk
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