Question

A force
F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a =5.0N/m^2
. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.

Answer 1

F = ax^2 plug in 0, and 6 which gives you 180J and 0J, subtract them and you get 180J

Answer 2

W=F(d) = 180(6) = 1080 watts

Answer 3

lol for reals?

Answer 4

Pretty sure broski

Answer 5

did you finish the whole thing?

Answer 6

Currently on #4

Answer 7

Wow! Your gettin it done early!

Answer 8

;) go on skype and we can talk