Fe2O3 + 2Al - Al2O3 + 2Fe

Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.

Help please!

Question

Fe2O3 + 2Al -> Al2O3 + 2Fe

Calculate the mass of iron metal (in grams) that can be prepared from 150 grams of aluminum and 250 grams of iron(III) oxide.

Help please!

anonymous · Answer

175

anonymous · Answer

can you explain a little bit please?

anonymous · Answer

Its a redox reaction: Basically the reaction is as follows: 
2Al+Fe2O3→Al2O3+2Fe

There are 
150÷27.0=5.5556
 moles of Aluminium,and
250÷(56×2+16×3)=1.5625
 moles of iron (III) oxide. Which material is the limiting reagent? Very obviously, iron oxide is the limiting reagent, as there is less of that material. 

Thus, the mass of iron that can be prepared will be the amount of iron in 1.5625 mol of iron (III) oxide. I think you will be able to figure that out:)