Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Question will be attached....I need help on C,D,E,F. And I am not sure if I did A &B right?

OpenStudy (anonymous):

OpenStudy (anonymous):

When it asks you to find f(x) at some number, like f(0), that means, using x = 0, find the height of the curve at that x value... in other words, find the y value. So your answers for A look correct... those two points are labeled on the curve, so it's not too hard to see what the y values are. Take another look at (B) and f(10)... find where x = 10 along the x-axis, then find where the curve is... is it positive or negative when x = 10?

OpenStudy (anonymous):

For part C, you need to imagine a horizontal line that goes through the point (0,4)... it is a flat line at height y = 4 that goes all the way across the graph... so see how many times it would cut through the curve.

OpenStudy (anonymous):

Part D asks which x-values create f(x) = -4? In other words, when the curve height is 4 below the x axis... when the curve is at -4, what is the corresponding x value? I will help you with one... over on the right of the curve, a point is labeled (16,-4), so an x value of 16 creates a value of f = -4. Look for other points like this...

OpenStudy (anonymous):

Part E asks for the set of allowable x values for this curve... so find the left-most and right-most x value, and write it in a bracket form like [ left-most x , right-most x ]

OpenStudy (anonymous):

So is B positive C is 2 times, i think D is -10, -4 E left=-12, 8 right= 22, -6

OpenStudy (anonymous):

Close :) I think you just made a typo on D. When x = -10, f(-10) = -4, so "-10" is one answer. The other is the other similar point that I listed... when x = -16, f(-16) = -4... so "16" is the other answer. For E, you only need the x values, not the points... so (-12,22) is the set of allowed x-values... any x value including or between -12 and 22 has a y-value shown on the curve. Beyond those x-values, the curve ends, so x values like -30 or 50 are NOT in the domain.

OpenStudy (anonymous):

So D is -10, 16 E ? is right or not f ? is right or not

OpenStudy (anonymous):

oh wait E is [-12, 22)

OpenStudy (anonymous):

yeah, that's better for E :)

OpenStudy (anonymous):

except careful with the brackets... both points -12 and 22 are in the domain... I can't remember if that means square brackets or curved, but it should be the same for both.

OpenStudy (anonymous):

I don't see a part F... did I miss something? I just saw A and B on one page and C, D, and E on the other.

OpenStudy (anonymous):

I have an example so there are written first in brackets then ending in parenthesis

OpenStudy (anonymous):

oops I for got to write F F is what is the range of F?

OpenStudy (anonymous):

so is F that [-6,8}

OpenStudy (anonymous):

does it show in the example whether both ends are included? You use one type of bracket/parenthesis to show that the point is in the set, and the other to show that it goes up to but does not include that point. It's the same idea as "greater" than versus "greater than or equal to" The range is the lowest level of the curve to the highest level.

OpenStudy (anonymous):

oh wait never mind they end in brackets sorry

OpenStudy (anonymous):

Yes, so -6 and 8... but I'm still unsure on the brackets. Both -6 and 8 are in the range... you would not say that f(x) must be like -6 < f(x) < 8.... you would say -6 <= f(x) <= 8. I'm just unsure how to write the brackets :)

OpenStudy (anonymous):

Ok, I looked it up :) a parenthesis means "does not include", and a square bracket means "including" so if you want all the x values between AND including -12 and 22, you write the domain as the interval [-12, 22]. And the range is [-6, 8], meaning all the values between and including -6 and 8 are possible for the height of f(x).

OpenStudy (anonymous):

alright thanks a lot.

OpenStudy (anonymous):

Glad to help :) Seems like you have the idea now... good luck!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!