Question

How do I use multiplication here to solve this problem? Please help.
x(x^2-4)/(x-1)^3 X X-1/X+2

Answer 1

Is it like this..\[\frac{x(x^2-4)}{(x-1)^3}*\frac{(x-1)}{(x+2)}\]

Answer 2

@desibaybee

Answer 3

If so ..\[\frac{x(x-2)(x+2)}{(x-1)^3}*\frac{(x-1)}{(x+2)}\]Now cut off common terms..

Answer 4

so x(x-2)/(x-1)^2

Answer 5

@Miyuru

Answer 6

Yeah..

Answer 7

Woooooooo! thank u

Answer 8

@Miyuru

Answer 9

No problem.. :)

Answer 10

@Miyuru SO IF IM USING DIVISION FOR THIS PROBLEM: 4X^2/7 / X^2/14

Answer 11

I SKIP FLIP AND THEN DIVIDE SO 4X^2/7 TIMES 14/X^2 = 4X2/1 SO = 8/1= 8

Answer 12

So my answer is correct?

Answer 13

yes

Answer 14

Yeah that's correct..:)

Answer 15

WOOOO THANK YOUUUUUUUUUU @Miyuru

Answer 16

thank You hun @uzumakhi
\

Answer 17

i do nothing here
don't thanx me

Answer 18

lol you told me my answer was correct

Answer 19

ok then
i accept your thanx..................lol

Answer 20

:D

Answer 21

@Miyuru Don't go yet I need you!

Answer 22

lol So to add this rational expression 10/3x^2+5/3x^2 I just add the numerators?

Answer 23

so 15/ 3x^2

Answer 24

Alright I am here.

Answer 25

Yeah

Answer 26

So that answer is correct too? @Miyuru

Answer 27

Yeap tht's correct..

Answer 28

if you have same denominaor you can add them simply

Answer 29

SO how would I subtract x+1/7x^2 - x-3/7x^2 ?

Answer 30

@Miyuru can you subtract x+1 - x-3 ?

Answer 31

Yeah just subtract..

Answer 32

How do I subtract that can you show me how to do this problem because I know they have the same denominator @Miyuru

Answer 33

x+1-(x-3)
x+1 -x +3
4

Answer 34

Yeah @uzumakhi is correct..

Answer 35

thanx @Miyuru

Answer 36

oh ok I see so why did you change -x-3 too -x+3?

Answer 37

@uzumakhi

Answer 38

If I have different denominators like this problem how would I solve this=
\[ \frac{ x+2 }{ 2^{2}-9x+10 } +\frac{ 1 }{ x-2 }\]

Answer 39

thats a 2x^2-9x+10 ^^^^

Answer 40

Take the lowest common multiple.....

Answer 41

First factorize \[2x^2-9x+10\]

Answer 42

@Miyuru how do I do that?

Answer 43

do it with middle term split

Answer 44

2x^2 - 5x -4x +10

Answer 45

As @uzumakhi said

Answer 46

so (x-4)(x-5)

Answer 47

\[\frac{ x+2 }{ (x-5)(x-2) }+\frac{ 1 }{ x-2 }\]

Answer 48

\[\frac{ x+2 }{ (x-4)(x-5) } + \frac{ 1 }{ x-2 }\]

Answer 49

how did you get x-2?