Question

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Answer 1

the fast easy way to graph the first one is to realize if you have 2 points on a line you can draw a line between them and bingo you have the line.
The x-intercept and y-intercept are two different points on the axes.
when x is zero what is y? put you point at (0, y)
when y is zero what is x? put your point at (x,0)
draw the line between them and bingo you have your line.

Answer 2

For the first one:
y-2x=-1
y -2(0) =-1 --> y=-1 (0,-1) is one point

for the x intercept
y-2x=-1
(0)-2x=-1 --> x = 1/2 (1/2, 0) is the other point

draw the line between and you have one line.
Repeat this with your second equation and see (at what point (X,Y)) do the two lines cross

Answer 3

none of my answers say that y is -1

Answer 4

It shouldn't your answers should be where the 2 lines intersect. I showed you how to
-draw- one of them. To get to the answer you need to repeat what I did to draw the second line, which should cross the first one. Your answer should be the point where the two lines cross.

The first line represents all the y values that satisfy the first equation.
The second line represents all the y values that satisfy the 2nd equation.

The point where they cross, that's where an (x,y) satisfies BOTH equations and as such is the solution to the -system(2)- of equations.

Answer 5

The answer is (1,1).

The question asked you to do it graphically, so I walked you through that.
You could have just solved the 2nd equation for X=4-3Y and then subbed into the 1st equation to find y

Answer 6

Thank you. The way you did it confused me.

Answer 7

If X = 4-3Y and
Y -2(x) = -1
then
Y-2(4-3Y)=-1
Y-8+6Y = -1
7Y = 7
Y=1;
Y-2X=-1
(1)-2(X)=-1
-2x =-2
x=1

Therefore the answer is (1,1)

Answer 8

They gave me this question too.
y + 2x = −1
3y − x = 4
help?

Answer 9

Sorry,
From the first equation
If Y+2X=-1 then Y = -1-2x
We can substitute this into the second equation
3Y-X=4 --> 3(-1-2x)-x=4
-3-6x-x=4
-7x =4+3
-7x=7
x=-1

Can you substitute -1 for X above and find Y?

Answer 10

-1,1?

Answer 11

\[\checkmark\] Correct:)

Answer 12

Okay I have this question but its confusing me.

2x + 3y = 3
3x – 2y = 11

What is the solution to the system?

A (–3, 3)

B (–1, –7)

C (1, –4)

D (3, –1)

For 2x + 3y = 3 I got y= 2/3 + 1
For 3x - 2y = 11 I got -1/2x -11/2

I'm confused.

Answer 13

For 2x + 3y = 3 I got y= (2/3)x + 1 **** lost a negative sign --> y=-(2/3)x+1

But there is an easier way to do this avoiding fraction

2x+3y=3 is the same thing as 4x+6y=6 ( i just multiplied both sides by 2)
3x-2y=11 is the same thing as -9x+6y=-33 (i just multiplied both sides by -3)

If I solve 4x+6y=6 for 6y, I can sub that value in for the 6y in the second equation
6y = 6-4x

so the second equation
-9x+6y=-33 becomes
-9x +(6-4x)=-33
-9x +6 -4x=-33
13x =-33 -6=-39
x = -39/13 = -3

Answer 14

There is only one answer with x = -3 :)

Answer 15

-3,3?

Answer 16

Yes. You can alway check the answer by subbing it into one or both of the equations.