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Increasing and decreasing intervals of 4x^2+4x-1
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do you know derivatives?
we have to complete the square
would it be \[\huge 4x^2+4x-4+4-1 \] for the first step of completing the square ?
yes
then \[\huge 4 (x-1)^2 -1\] ? :S
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when you multiply that out it doesnt give you 4x^2+4x-4+4-1
try this one 4(x+(1/2))^2 -2
i dont get where the 1/2 comes from :S
i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the -1 over, and dividing by 4 then complete the square
why does it have to be 1 ?
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because thats what the formula says
oh so it applies at all equations ?
it applies to quadratics with a leading coefficient of 1
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