Question

Solve by subsititution method or the add-or-minus-method

Answer 1

\[\frac{ 1 }{ 3 }a-\frac{ 2 }{ 3 }b=1\]

Answer 2

\[a+b+7=0\]

Answer 3

Is the answer \[-\frac{ 19 }{ 3 }, -\frac{ 8 }{ 3 }\]

Answer 4

multiply our first equation by three

Answer 5

Divide the second equation by -1/3

Answer 6

o3o...I just solved for a and i got a=2b+1...

Answer 7

almost
\[\frac{ 1 }{ 3 }a-\frac{ 2 }{ 3 }b=1\]
multiplying by three
\[a-2b=3\]
\[a=2b+3\]
, now substitute \(a\) into your second equation

\[a+b+7=0\]
\[(2b+3)+b+7=0\]
and solve for \(b\)

Answer 8

How'd you get +3? ><''

Answer 9

one multiplied by three is three

Answer 10

mk well first... i moved 2/3b to the other side...

Answer 11

ohhhh.

Answer 12

XD

Answer 13

So then...

Answer 14

b=-10/3

Answer 15

-23/3,-1/3?

Answer 16

-10/3*

Answer 17

Right?... ><''

Answer 18

almost

Answer 19

Grahhh. I suck at this. *ashamed*

Answer 20

Let me try again.

Answer 21

mk...SO.

Answer 22

2b+3+b+7=0.

Answer 23

3b+10=0
3b=-10
b=-10/3

Answer 24

you got \(b\) right

Answer 25

a=2(-10/3)+1
a=-20/3+1

Answer 26

and then....

Answer 27

\[a=2b+3\]
\[a=2\left(-\frac{10}3\right)+3\]

Answer 28

ohhh. geez I see XD

Answer 29

I'm a dumbcluck.

Answer 30

dont forget the three

Answer 31

-17/3 :P

Answer 32

not quite

Answer 33

Arrgh.

Answer 34

Wouldn't it turn out to be a=-20/3+3/3 though?

Answer 35

3=9/3

Answer 36

O3o...man...I'm really out of it today...omigod what's wrong with me...

Answer 37

Solving simultaneous equations is very tricky

Answer 38

XD Thank you though. For fixing my dumbcluck-ness.

Answer 39

So then....11/3 negative...

Answer 40

Can I ask one more question?

Answer 41

that is \(a\) !

Answer 42

, sure

Answer 43

Okay so... the equations are...

Answer 44

\[\frac{ 5a }{ 6 }-\frac{ b }{ 3 }=6\]
\[a+2b=0\]

Answer 45

Okay so... a=-2b
5(-2b)/6-b/3
-10b/6-b/3=6

Answer 46

that looks right so far

Answer 47

mk...how to I solve -10b/6-b/3=6? I totally forgot.

Answer 48

\[-\frac{10}6b-\frac 13b=6\]
in the first fraction there is a common factor of 2 ,
cancel this,

then add the fractions

Answer 49

Okay...

Answer 50

-6b/3=6?

Answer 51

And then...

Answer 52

I um...multiply both sides by 3.

Answer 53

-3.

Answer 54

yeah \(b=-3\),
great work

what is \(a\)

Answer 55

a=6

Answer 56

You're just now solving it?

Answer 57

m hm..

Answer 58

thats right

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