Question

Find any points of discontinuity for the rational function.What are the points of discontinuity? Are they all removable?

ill post pic

Answer 1

7 and 3 are the points of discontinuity of the function because here the the function sdenominator tends to 0 and the fonction itself tends to infinity

Answer 2

for discountinuity put denominator =0
x^2-10x+21=0
x^2-7x-3x+21=0
x(x-7)-3(x-7)=0
(x-7)(x-3)=0
at x=7 and x=3 it is discontinous
can be removed
y=x-7)(x-3)/x-7)(x-3)
y=1

Answer 3

x = –7, x = –3; no would that be it ?

Answer 4

no points of dicontinuity are 7 and 3 the way to remove them is to define the function in a new way by taking y=1

Answer 5

x = 1, x = –8, x = –2; yes ?

Answer 6

or x = –1, x = 8, x = 2; no

Answer 7

at x=7 and x=3

Answer 8

no x=7,3 are points of discontinuity

Answer 9

x = 7, x = 3; yes <-------------- this ?? one right ?

Answer 10

yes

Answer 11

omg i was solving it wrong thanks !!

Answer 12

see my post that i have send

Answer 13

i see now