Question

Factor completely using the difference of squares along with factoring by grouping.

7n-7p+n^2-p^2

Answer 1

So far I factored the first two terms by using factoring by grouping and got 7(n-p). Then I factored the last two terms by using the difference of squares and got. (n-p)(n^2-np+p^2) So altogether it's 7(n-p)(n-p)(n^2-np+p^2) So then it ends up being 7(n-p)^2(n^2-np+p^2) right?

Answer 2

You will have the form (n + x)^2 - (p + x)^2 for a particular value of "x".

Answer 3

cause the only choices are
a.prime
b. 7(n-p)+n^2+p^2
c. 7(n-p)(n+p)
d. (n-p)(7+n+p)

Answer 4

which would be the answer then?

Answer 5

So it would be D

Answer 6

how so?

Answer 7

Because if you add and subtract pn you get -pn + pn +7n - 7p + n^2 - p^2 so you can work with those 6 terms. That's 2 in addition to the original 4.