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GT ECE 4560 - Intro to Automation & Robotics 15 Online
OpenStudy (anonymous):

In problem 1.b what is the computed twist from last weeks hw?

OpenStudy (anonymous):

This would be the xi = ln(inv(gi)*gf). You can just look at the solutions for last week's homework to get the numerical value if you like.

OpenStudy (anonymous):

What is the numerical value for the twist?

OpenStudy (anonymous):

Oh I see it is not explicitly given in HW12 solutions. You can compute it by ln(inv(gi)*gf). I think the answer is [0.0218,0.1206,.2618] but that's not a guatantee.

OpenStudy (anonymous):

For part b is the body velocity equal to inv(g0'*exp(twist*t))*g0'*twist*exp(twist*t)

OpenStudy (anonymous):

Yes just be careful to apply the transformation properly to a twist.

OpenStudy (anonymous):

When i run the code it is not coming up with an answer. It just keeps running.

OpenStudy (anonymous):

What code are you referring to?

OpenStudy (anonymous):

The ode45 with xdot=inv(J)*body velocity

OpenStudy (anonymous):

I'm not sure what the problem is. Look over the solutions from homework 1 or whatever other homework you had to do ode45 into make sure you re implementing it properly. I can look at it tomorrow after class if you still can't get it. Gotta go for the night. Good luck.

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