Let f(x) = (x^2 -5x - 14)/(x-7). Identify another function that agrees with f(x) at all but one point.

Question

anonymous · Answer

Could you define a piecewise function?
e.g 
$$f(x)=(x^2-5x-14)/(x-7) for ( -\infty,2)  and  (2,\infty)$$
so the function does not include x=2, yet agrees everywhere else?

anonymous · Answer

yes, that sounds correct

anonymous · Answer

wait, shouldn't it be 7 instead of 2? Since it would make the function undefined?

anonymous · Answer

The original function itself does not contain 7 in domain..So, your answer would be something like this (-infinity,2)U(2,infinity)-{7}

anonymous · Answer

The domain of the function in the question is R-{7}
So, your answer satisfies every value except at x=2

anonymous · Answer

the function you are looking for is $g(x)=x-2$

anonymous · Answer

scratch that, it is $g(x)=x+2$ sorry

anonymous · Answer

Toatally forgot it @satellite73

anonymous · Answer

*totally